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    • Tree Traverse
    • Iteration based traverse
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      • Max width of binary tree
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      • Lowest common ancestor (LCA) for Binary Tree and BST
      • Subproblem-based Approach for Resolving Max Value on Trees
      • Path sum III
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    • 1. Binary Search
    • 2. Two Pointer
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    • 9. Prefix Sum
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    • 14. Tree
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    • 16. Bit manipulation
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      • Classic DP Problems
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  • Blind 75
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  • Iteration based preorder
  • Iteration based inorder
  • Iteration based postorder
  1. Tree

Iteration based traverse

Iteration based preorder

public List<Integer> preorderTraversal(TreeNode root) {
        List<Integer> res = new ArrayList<>();
        if (root == null) {
            return res;
        }
        Stack<TreeNode> stack = new Stack<>();
        stack.push(root);
        while (!stack.isEmpty()) {
            root = stack.pop();
            res.add(root.val);
            if (root.right != null) {
                stack.push(root.right);
            }
            if (root.left != null) {
                stack.push(root.left);
            }
        }
        return res;
    }

Iteration based inorder

public List<Integer> inorderTraversal(TreeNode root) {
        List<Integer> res = new ArrayList<>();
        if (root == null) {
            return res;
        }
        Stack<TreeNode> stack = new Stack<>();
        while (root != null || !stack.isEmpty()) {
            while (root != null) {
                stack.push(root);
                root = root.left;
            }
            root = stack.pop();
            res.add(root.val);
            root = root.right;
            
        }

        return res;

    }

Iteration based postorder


public List<Integer> postorderTraversal(TreeNode root) {
        List<Integer> res = new ArrayList<>();
        if (root == null) {
            return res;
        }

        Stack<TreeNode> stack = new Stack<>();
        stack.add(root);
        while (!stack.isEmpty()) {
            root = stack.pop();
            res.add(0, root.val);
            if (root.left != null) {
                stack.add(root.left);
            }
            if (root.right != null) {
                stack.add(root.right);
            }
        }
        return res;
    }
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Last updated 2 years ago